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Random maths


davenportram

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Is it four?

split into groups of three... so three times to identify the larger group of cans. You can use the groups to find the average weight of each can. Then you weigh each can from the heaviest group, so it could be five if the first two cans weigh the same. Makes sense in my head.

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Is it four?

split into groups of three... so three times to identify the larger group of cans. You can use the groups to find the average weight of each can. Then you weigh each can from the heaviest group, so it could be five if the first two cans weigh the same. Makes sense in my head.

Good start three in each side.

If they balance then where must the heavy tin be?

If they don't balance where must the heavy tin be?

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Good start three in each side.

If they balance then where must the heavy tin be?

If they don't balance where must the heavy tin be?

Ooops thought it was a single scale...

Yeah, if you weigh two, if they balance then you have the heaviest can spare. If not then the heaviest is one of those, so you swap one for the other of the three

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2..

It's easy, you have 9 tins..

Weigh 3 on each side, which is 6 (and leaves 3)... If one side is heavier, it leaves 3.. If not, it's one of the remaining 3..

Then weigh 2 of the 3.. (one on each side and the other tin left off) If one tin is heavier the scale will show, if not then it's the remaining tin you have left on the side..

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